Решите неравенствоlog2(32x)log2x−5+log2x−5log2(32x)⩾log2(x16)+18log22x−25.\frac{\log_{2}(32x)}{\log_{2} x - 5} + \frac{\log_{2} x - 5}{\log_{2}(32x)} \geqslant \frac{\log_{2} \left(x^{16}\right) + 18}{\log_{2}^{2} x - 25}.log2x−5log2(32x)+log2(32x)log2x−5⩾log22x−25log2(x16)+18.▸Ответ(0; 132)∪{16}∪(32; +∞)\left(0;\ \frac{1}{32}\right) \cup \{16\} \cup (32;\ +\infty)(0; 321)∪{16}∪(32; +∞).