Решите неравенствоlog4(64x)log4x−3+log4x−3log4(64x)⩾log4(x4)+16log42x−9.\frac{\log_{4}(64x)}{\log_{4} x - 3} + \frac{\log_{4} x - 3}{\log_{4}(64x)} \geqslant \frac{\log_{4} \left(x^{4}\right) + 16}{\log_{4}^{2} x - 9}.log4x−3log4(64x)+log4(64x)log4x−3⩾log42x−9log4(x4)+16.▸Ответ(0; 164)∪{4}∪(64; +∞)\left(0;\ \frac{1}{64}\right) \cup \{4\} \cup (64;\ +\infty)(0; 641)∪{4}∪(64; +∞).