Найдите корень уравнения 112x−20=14\sqrt{\dfrac1{12x-20}}=\dfrac1412x−201=41▸Ответ3▸Решение112x−20=14\sqrt{\dfrac1{12x-20}}=\dfrac1412x−201=41 112x−20=14\dfrac1{\sqrt{12x-20}}=\dfrac1412x−201=41 12x−20=4\sqrt{12x-20}=412x−20=4 12x−20=4212x-20=4^212x−20=42 12x−20=1612x-20=1612x−20=16 12x=16+2012x=16+2012x=16+20 12x=3612x=3612x=36 x=3612=3x=\dfrac{36}{12}=3x=1236=3