Найдите кореь уравнения 58x+1=1,25⋅48x+15^{8x+1}=1,25\cdot 4^{8x+1}58x+1=1,25⋅48x+1▸Ответ0▸Решение58x+1=1,25⋅48x+15^{8x+1}=1,25\cdot 4^{8x+1}58x+1=1,25⋅48x+1 58x+148x+1=1,25\frac{5^{8x+1}}{4^{8x+1}}=1,2548x+158x+1=1,25 (54)8x+1=1,25\left(\frac{5}{4}\right)^{8x+1}=1,25(45)8x+1=1,25 1,258x+1=1,2511,25^{8x+1}=1,25^11,258x+1=1,251 8x+1=18x+1=18x+1=1 8x=1−18x=1-18x=1−1 x=0x=0x=0