Задание 571

$$\log_3(9x+24)=\log_936$$

$$\log_3(9x+24)=\frac{1}{2}\log_336$$

$$\log_3(9x+24)=2\cdot \frac{1}{2}\log_36$$

$$\log_3(9x+24)=\log_36$$

$$9x+24=6$$

$$9x=6-24$$

$$9x=-18$$

$$x=-2$$