Решите неравенство2⋅4x−22⋅4x−2−1⩾74x−1+4016x−9⋅4x+8.\frac{2\cdot 4^{x-2}}{2\cdot 4^{x-2}-1}\geqslant\frac{7}{4^{x}-1}+\frac{40}{16^{x}-9\cdot 4^{x}+8}.2⋅4x−2−12⋅4x−2⩾4x−17+16x−9⋅4x+840.▸Ответ(−∞;0)∪{1}∪(32;+∞)(-\infty;0)\cup\{1\}\cup\left(\frac{3}{2};+\infty\right)(−∞;0)∪{1}∪(23;+∞)