Решите неравенство25x2−120x+144log2(4x−8)−log2(2x+1)⩽0.\frac{25x^{2} - 120x + 144}{\log_{2}\left(4^{x} - 8\right) - \log_{2}\left(2^{x+1}\right)} \leqslant 0.log2(4x−8)−log2(2x+1)25x2−120x+144⩽0.▸Ответ(1,5;2)∪{2,4}(1{,}5; 2) \cup \{2{,}4\}(1,5;2)∪{2,4}.