Решите неравенство8x3−4x2−2x+116x2−4⋅4x2+4⩽0.\frac{8x^{3} - 4x^{2} - 2x + 1}{16^{x^{2}} - 4 \cdot 4^{x^{2}} + 4} \leqslant 0.16x2−4⋅4x2+48x3−4x2−2x+1⩽0.▸Ответ(−∞; −22)∪(−22; −12]∪{12}\left(-\infty;\ -\frac{\sqrt{2}}{2}\right) \cup \left(-\frac{\sqrt{2}}{2};\ -\frac{1}{2}\right] \cup \left\{\frac{1}{2}\right\}(−∞; −22)∪(−22; −21]∪{21}.