Решите неравенствоx3+x2−x−14x2−8⋅2x2+16⩾0.\frac{x^{3} + x^{2} - x - 1}{4^{x^{2}} - 8 \cdot 2^{x^{2}} + 16} \geqslant 0.4x2−8⋅2x2+16x3+x2−x−1⩾0.▸Ответ{−1}∪[1;2)∪(2;+∞)\{-1\} \cup \left[1; \sqrt{2}\right) \cup \left(\sqrt{2}; +\infty\right){−1}∪[1;2)∪(2;+∞).