Решите неравенствоlog2(8x)⋅log3(27x)x2−∣x∣⩽0.\frac{\log_{2}(8x) \cdot \log_{3}(27x)}{x^{2} - |x|} \leqslant 0.x2−∣x∣log2(8x)⋅log3(27x)⩽0.▸Ответ(0; 127]∪[18; 1)\left(0;\ \frac{1}{27}\right] \cup \left[\frac{1}{8};\ 1\right)(0; 271]∪[81; 1).