Решите неравенствоlog4((x−5)(x2−2x−15))+1⩾0,5⋅log2(x−5)2.\log_{4}\left((x - 5)\left(x^{2} - 2x - 15\right)\right) + 1 \geqslant 0{,}5 \cdot \log_{2}(x - 5)^{2}.log4((x−5)(x2−2x−15))+1⩾0,5⋅log2(x−5)2.▸Ответ[−114;5)∪(5;+∞)\left[-\frac{11}{4}; 5\right) \cup (5; +\infty)[−411;5)∪(5;+∞).