Решите неравенство1+5log4x−3+6log42x−log4(64x6)+12⩾0.1 + \frac{5}{\log_{4} x - 3} + \frac{6}{\log_{4}^{2} x - \log_{4} \left(64x^{6}\right) + 12} \geqslant 0.1+log4x−35+log42x−log4(64x6)+126⩾0.▸Ответ(0; 1]∪[4; 64)∪(64; +∞)(0;\ 1] \cup [4;\ 64) \cup (64;\ +\infty)(0; 1]∪[4; 64)∪(64; +∞).