Решите неравенствоlog5(25x)log5x−2+log5x−2log5(25x)⩾6−log5(x4)log52x−4.\frac{\log_{5}(25x)}{\log_{5} x - 2} + \frac{\log_{5} x - 2}{\log_{5}(25x)} \geqslant \frac{6 - \log_{5} \left(x^{4}\right)}{\log_{5}^{2} x - 4}.log5x−2log5(25x)+log5(25x)log5x−2⩾log52x−46−log5(x4).▸Ответ(0; 125)∪{15}∪(25; +∞)\left(0;\ \frac{1}{25}\right) \cup \left\{\frac{1}{5}\right\} \cup (25;\ +\infty)(0; 251)∪{51}∪(25; +∞).