Решите неравенствоlog4(16x4)+11log42x−9⩾−1.\frac{\log_{4}\left(16x^{4}\right) + 11}{\log_{4}^{2} x - 9} \geqslant -1.log42x−9log4(16x4)+11⩾−1.▸Ответ(0;164)∪{116}∪(64;+∞)\left(0; \frac{1}{64}\right) \cup \left\{\frac{1}{16}\right\} \cup (64; +\infty)(0;641)∪{161}∪(64;+∞).