Решите неравенствоlog22(x2−9)−9log2(x2−9)+20⩾0.\log_{2}^{2}\left(x^{2} - 9\right) - 9\log_{2}\left(x^{2} - 9\right) + 20 \geqslant 0.log22(x2−9)−9log2(x2−9)+20⩾0.▸Ответ(−∞;−41]∪[−5;−3)∪(3;5]∪[41;+∞)\left(-\infty; -\sqrt{41}\right] \cup [-5; -3) \cup (3; 5] \cup \left[\sqrt{41}; +\infty\right)(−∞;−41]∪[−5;−3)∪(3;5]∪[41;+∞).