Решите неравенство x2log243(4−x)⩽log3(x2−8x+16)x^{2}\log_{243}(4-x) \leqslant \log_{3}(x^{2}-8x+16)x2log243(4−x)⩽log3(x2−8x+16).▸Ответx∈[−10;3]∪[10;4)x \in [-\sqrt{10}; 3] \cup [\sqrt{10}; 4)x∈[−10;3]∪[10;4).