Решите неравенство (16x−2⋅4x+1)2−23⋅(16x−2⋅4x+1)+112⩾0(16^{x}-2 \cdot 4^{x}+1)^{2}-23 \cdot (16^{x}-2 \cdot 4^{x}+1)+112 \geqslant 0(16x−2⋅4x+1)2−23⋅(16x−2⋅4x+1)+112⩾0.▸Ответx∈(−∞;log4(1+7)]∪[log45;+∞)x \in \left(-\infty; \log_{4}(1+\sqrt{7})\right] \cup [\log_{4} 5; +\infty)x∈(−∞;log4(1+7)]∪[log45;+∞).