Задание 3169

$$q=114-2p, r(p)=pq\Rightarrow$$

$$r(p)=p(114-2p)=114p-2p^2$$

$$1260=114p-2p^2$$

$$-2p^2+114p-1260=0$$

$$2p^2-114p+1260=0$$

$$p^2-57p+630=0$$

$D=(-57)^2-4\cdot 630=$$3249-2520=729$

$p_1=\frac{-(-57)+\sqrt{729} }{2}=$$\dfrac{57+27}2=\dfrac{84}2=42$

$$p_2=\dfrac{57-27}2=\dfrac{30}2=15$$

$$15< 42$$