Задание 2994

$$\left(\dfrac1{15} \right)^{14x+9}=\dfrac1{225}$$

$$\left(\dfrac1{15} \right)^{14x+9}=\left( \dfrac1{15} \right)^2$$

$$14x+9=2$$

$$14x=2-9$$

$$14x=-7$$

$$x=\dfrac{-7}{14}$$

$$x=-0,5$$