Задание 2993

$$\sqrt{\dfrac{8-5x}3 }=6$$

$$\left(\sqrt{\dfrac{8-5x}3 }\right)^2=6^2$$

$$\dfrac{8-5x}3=36$$

$$8-5x=36\cdot 3$$

$$8-5x=108$$

$$-5x=108-8$$

$$-5x=100$$

$$x=\dfrac{100}{-5}$$

$$x=-20$$