Задание 1300

Приведем числа $0,7; 0,8; \frac2{15}; \frac4{15}; \frac7{15}; \frac{11}{15}$ к общему знаменателю:

$$0,7 = \frac7{10} = \frac{21}{30}$$

$$0,8 = \frac8{10} = \frac{24}{30}$$

1)\frac2{15} = \frac{4}{30}<\frac{21}{30}<0,7

2)\frac4{15} = \frac8{30}<\frac{21}{30}<0,7

3)\frac7{15} = \frac{14}{30}<\frac{21}{30}<0,7

$4)\frac{11}{15} = \frac{22}{30};$\frac{21}{30}<\frac{22}{30}<\frac{24}{30}$\Rightarrow \frac{11}{15}\in [0,7;0,8]$